JEE Main 20241 Feb, Evening shiftChemistryMediumChemical Thermodynamics84× since 2002For a certain reaction at 300 K, K=10300 \mathrm{~K}, \mathrm{~K}=10300 K, K=10, then ΔG∘\Delta \mathrm{G}^{\circ}ΔG∘ for the same reaction is - ____________ ×10−1 kJ mol−1\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}×10−1 kJ mol−1. (Given R=8.314JK−1 mol−1\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}R=8.314JK−1 mol−1 )Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
