JEE Main 20264 Apr, Evening shiftMathematicsEasyStatistics and Probability258× since 2002For 10 observations x1,x2,…,x10x_1,x_2,\dots,x_{10}x1,x2,…,x10, if ∑i=110(xi+2)2=180\sum_{i=1}^{10}(x_i+2)^2=180∑i=110(xi+2)2=180 and ∑i=110(xi−1)2=90\sum_{i=1}^{10}(x_i-1)^2=90∑i=110(xi−1)2=90, then their standard deviation is:AOption A. 2BOption B. 3\sqrt33COption C. 222\sqrt222DOption D. 3CheckSkip · show solution
