JEE Main 20254 Apr, Evening shiftPhysicsEasyOscillations and Waves185× since 2002Displacement of a wave is expressed as x(t)=5cos(628t+π2)x(t) = 5\cos\left(628t + \frac{\pi}{2}\right)x(t)=5cos(628t+2π) m. The wavelength of the wave when its velocity is 300 m/s is : (π=3.14\pi = 3.14π=3.14)AOption A. 0.5 mBOption B. 5 mCOption C. 0.33 mDOption D. 3 mCheckSkip · show solution