JEE Main 202628 Jan, Evening shiftMathematicsEasyTrigonometry118× since 2002Considering the principal values of inverse trigonometric functions, the value of the expression tan(2sin−1(213)−2cos−1(310))\tan\left(2\sin^{-1}\left(\frac{2}{\sqrt{13}}\right) - 2\cos^{-1}\left(\frac{3}{\sqrt{10}}\right)\right)tan(2sin−1(132)−2cos−1(103)) is equal to :AOption A. −3356-\frac{33}{56}−5633BOption B. 3356\frac{33}{56}5633COption C. 1663\frac{16}{63}6316DOption D. −1663-\frac{16}{63}−6316CheckSkip · show solution
