Consider the following electrochemical cell at 298K: Pt|HSnO₂^-(aq)|Sn(OH)₆²⁻(aq)|OH^-(aq)|Bi₂O₃(s)|Bi(s). If the reaction quotient at a given time is 10⁶, then the cell EMF (E cell) is _ _ _ ×10⁻¹ V (Nearest integer). Given the standard half-cell reduction potential as E° Bi₂O₃/Bi,OH^- =-0.44 V and E°_ Sn(OH)₆²⁻/HSnO₂^-,OH^- =-0.90 V

Redox Reactions and Electrochemistry: JEE Main 2026 Chemistry question

JEE Main 2026 · 22 Jan, Morning shift · Q75

JEE Main 202622 Jan, Morning shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

Consider the following electrochemical cell at 298K:

\mathrm{Pt|HSnO_2^-(aq)|Sn(OH)_6^{2-}(aq)|OH^-(aq)|Bi_2O_3(s)|Bi(s)}

. If the reaction quotient at a given time is

10^{6}

, then the cell EMF (

E_{cell}

) is ______

\times10^{-1}

V (Nearest integer). Given the standard half-cell reduction potential as

E^\circ_{\mathrm{Bi_2O_3/Bi,OH^-}}=-0.44

V and

E^\circ_{\mathrm{Sn(OH)_6^{2-}/HSnO_2^-,OH^-}}=-0.90

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 Redox Reactions and Electrochemistry Question with Solution (22 Jan Morning shift, Q75) | JEE Arc