Based on the data given below: E°_ Cr₂O₇²⁻/Cr³⁺ = 1.33 V, E°_ Cl₂/Cl⁻ = 1.36 V, E°_ MnO₄^-/Mn²⁺ = 1.51 V, E°_ Cr³⁺/Cr = -0.74 V, the strongest reducing agent is:

Redox Reactions and Electrochemistry: JEE Main 2025 Chemistry question

JEE Main 2025 · 24 Jan, Evening shift · Q63

JEE Main 202524 Jan, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

Based on the data given below:

E^\circ_{\mathrm{Cr_2O_7^{2-}/Cr^{3+}}} = 1.33

E^\circ_{\mathrm{Cl_2/Cl^{-}}} = 1.36

E^\circ_{\mathrm{MnO_4^-/Mn^{2+}}} = 1.51

E^\circ_{\mathrm{Cr^{3+}/Cr}} = -0.74

V, the strongest reducing agent is:

JEE Main 2025 · 24 Jan, Evening shift · Q63

JEE Main 202524 Jan, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

Based on the data given below:

E^\circ_{\mathrm{Cr_2O_7^{2-}/Cr^{3+}}} = 1.33

E^\circ_{\mathrm{Cl_2/Cl^{-}}} = 1.36

E^\circ_{\mathrm{MnO_4^-/Mn^{2+}}} = 1.51

E^\circ_{\mathrm{Cr^{3+}/Cr}} = -0.74

V, the strongest reducing agent is: