PhysicsHard120×since 2002Q6828Average force exerted on a non-reflecting surface at normal incidence is 2.4×10−4 N2.4 \times 10^{-4} \mathrm{~N}2.4×10−4 N. If 360 W/cm2360 \mathrm{~W} / \mathrm{cm}^2360 W/cm2 is the light energy flux during span of 1 hour 30 minutes, Then the area of the surface is:A20 m220 \mathrm{~m}^220 m2B0.2 m20.2 \mathrm{~m}^20.2 m2C0.1 m20.1 \mathrm{~m}^20.1 m2D0.02 m20.02 \mathrm{~m}^20.02 m2Check answerSkip