At a given point of time the value of displacement of a simple harmonic oscillator is given as y=A cos (30^(°)). If amplitude is 40 ~cm and kinetic energy at that time is 200 ~J, the value of force constant is 1.0 × 10ˣ ~Nm⁻¹. The value of x is _ _ _ _ _ _.

Oscillations and Waves: JEE Main 2023 Physics question

JEE Main 2023 · 13 Apr, Morning shift · Q71

JEE Main 202313 Apr, Morning shiftPhysicsMediumOscillations and Waves185× since 2002

At a given point of time the value of displacement of a simple harmonic oscillator is given as

\mathrm{y}=\mathrm{A} \cos \left(30^{\circ}\right)

. If amplitude is

40 \mathrm{~cm}

and kinetic energy at that time is

200 \mathrm{~J}

, the value of force constant is

1.0 \times 10^{x} ~\mathrm{Nm}^{-1}

. The value of

x

is ____________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Oscillations and Waves Question with Answer (13 Apr Morning shift, Q71) | JEE Arc