PhysicsMedium120×since 2002Q6746An electromagnetic wave is represented by the electric field E→=E0n^sin[ωt+(6y−8z)]\overrightarrow E = {E_0}\widehat n\sin \left[ {\omega t + \left( {6y - 8z} \right)} \right]E=E0nsin[ωt+(6y−8z)] . Taking unit vectors in x, y and z directions to be i^,j^,k^\widehat i,\widehat j,\widehat ki,j,k , the direction of propagation s^\widehat ss, is :As^=3i^−4j^5\widehat s = {{3\widehat i - 4\widehat j} \over 5}s=53i−4jBs^=−4k^+3j^5\widehat s = {{ - 4\widehat k + 3\widehat j} \over 5}s=5−4k+3jCs^=(−3j^+4k^5)\widehat s = \left( {{{ - 3\widehat j + 4\widehat k} \over 5}} \right)s=(5−3j+4k)Ds^=4j^−3k^5\widehat s = {{4\widehat j - 3\widehat k} \over 5}s=54j−3kCheck answerSkip