JEE Main 202524 Jan, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002An alternating current is given by I=IAsinωt+IBcosωtI=I_A\sin\omega t+I_B\cos\omega tI=IAsinωt+IBcosωt. The r.m.s current will beAOption A. ∣IA+IB∣2\frac{|I_A+I_B|}{\sqrt2}2∣IA+IB∣BOption B. IA2+IB2\sqrt{I_A^2+I_B^2}IA2+IB2COption C. IA2+IB22\frac{\sqrt{I_A^2+I_B^2}}{2}2IA2+IB2DOption D. IA2+IB22\sqrt{\frac{I_A^2+I_B^2}{2}}2IA2+IB2CheckSkip · show solution
