MathematicsEasy129×since 2002Q5067All the pairs (x, y) that satisfy the inequality 2sin2x−2sinx+5.14sin2y≤1{2^{\sqrt {{{\sin }^2}x - 2\sin x + 5} }}.{1 \over {{4^{{{\sin }^2}y}}}} \le 12sin2x−2sinx+5.4sin2y1≤1 also satisfy the equationAsin x = |sin y|Bsin x = 2sin yC2 sin x = sin yD2 |sin x | = 3 sin yCheck answerSkip