MathematicsMedium127×since 2002Q3029A square is inscribed in the circle x2+y2−10x−6y+30=0x^2+y^2-10 x-6 y+30=0x2+y2−10x−6y+30=0. One side of this square is parallel to y=x+3y=x+3y=x+3. If (xi,yi)\left(x_i, y_i\right)(xi,yi) are the vertices of the square, then Σ(xi2+yi2)\Sigma\left(x_i^2+y_i^2\right)Σ(xi2+yi2) is equal to:A152B148C156D160Check answerSkip