PhysicsMedium120×since 2002Q6803A point source of 100 W100 \mathrm{~W}100 W emits light with 5%5 \%5% efficiency. At a distance of 5 m5 \mathrm{~m}5 m from the source, the intensity produced by the electric field component is:A140πWm2\frac{1}{40 \pi} \frac{W}{m^2}40π1m2WB110πWm2\frac{1}{10 \pi} \frac{W}{m^2}10π1m2WC120πWm2\frac{1}{20 \pi} \frac{W}{m^2}20π1m2WD12πWm2\frac{1}{2 \pi} \frac{W}{m^2}2π1m2WCheck answerSkip