A plane electromagnetic wave is moving in free space with velocity c = 3 × 10⁸ m/s and its electric field is given as E = 54 sin (kz - ω t)j V/m, where j is the unit vector along y-axis. The magnetic field vector B of the wave is:

(C) -1.8 × 10⁻⁷ sin (kz - ω t)i T

(A) 1.4 × 10⁻⁷ sin (kz - ω t)k T

(B) +1.8 × 10⁻⁷ sin (kz - ω t)i T

(D) 1.4 × 10⁻⁷ sin (kz - ω t)i T

Electromagnetic Waves: JEE Main 2026 Physics question

JEE Main 2026 · 28 Jan, Evening shift · Q26

JEE Main 202628 Jan, Evening shiftPhysicsMediumElectromagnetic Waves120× since 2002

A plane electromagnetic wave is moving in free space with velocity

c = 3 \times 10^8

m/s and its electric field is given as

\vec{E} = 54\sin(kz - \omega t)\hat{j}

V/m, where

\hat{j}

is the unit vector along y-axis. The magnetic field vector

\vec{B}

of the wave is :

JEE Main 2026 Electromagnetic Waves Question with Solution (28 Jan Evening shift, Q26) | JEE Arc