A physical quantity Q is related to four observables a, b, c, d as follows: Q = (ab⁴)/cd where, a = (60 ± 3) Pa; b = (20 ± 0.1) m; c = (40 ± 0.2) Nsm⁻² and d = (50 ± 0.1) m, then the percentage error in Q is x/1000, where x = _ _ _.

Units and Measurements: JEE Main 2025 Physics question

JEE Main 2025 · 29 Jan, Evening shift · Q49

JEE Main 202529 Jan, Evening shiftPhysicsMediumUnits and Measurements122× since 2002

A physical quantity Q is related to four observables a, b, c, d as follows :

Q = \frac{ab^4}{cd}

where,

a = (60 \pm 3)

Pa;

b = (20 \pm 0.1)

c = (40 \pm 0.2)

\mathrm{Nsm^{-2}}

and

d = (50 \pm 0.1)

m, then the percentage error in Q is

\frac{x}{1000}

, where

x =

______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2025 Units and Measurements Question with Solution (29 Jan Evening shift, Q49) | JEE Arc