A particle of mass 'm' is moving in time 't' on a trajectory given by r = 10α t² i + 5β (t - 5) j Where α and β are dimensional constants. The angular momentum of the particle becomes the same as it was for t = 0 at time t = _ _ _ _ _ _ seconds.

Rotational Motion: JEE Main 2021 Physics question

JEE Main 2021 · 25 Jul, Morning shift · Q68

JEE Main 202125 Jul, Morning shiftPhysicsMediumRotational Motion140× since 2002

A particle of mass 'm' is moving in time 't' on a trajectory given by

\overrightarrow r = 10\alpha {t^2}\widehat i + 5\beta (t - 5)\widehat j

Where

\alpha

and

\beta

are dimensional constants. The angular momentum of the particle becomes the same as it was for t = 0 at time t = ____________ seconds.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Rotational Motion Question with Answer (25 Jul Morning shift, Q68) | JEE Arc