JEE Main 202227 Jun, Evening shiftPhysicsMediumLaws of Motion70× since 2002
A mass of 10 kg is suspended vertically by a rope of length 5 m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is = tan^1 (x 10^1). The value of x is ____________.
(Given, g = 10 m/s²)