A force on an object of mass 100 g is (10 i + 5 j) N. The position of that object at t = 2 s is (a i + b j) m after starting from rest. The value of a/b will be _ _ _ _ _ _.

Laws of Motion: JEE Main 2022 Physics question

JEE Main 2022 · 25 Jun, Morning shift · Q67

JEE Main 202225 Jun, Morning shiftPhysicsMediumLaws of Motion70× since 2002

A force on an object of mass 100 g is

\left( {10\widehat i + 5\widehat j} \right)

N. The position of that object at t = 2 s is

\left( {a\widehat i + b\widehat j} \right)

m after starting from rest. The value of

{a \over b}

will be ___________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 Laws of Motion Question with Answer (25 Jun Morning shift, Q67) | JEE Arc