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JEE Main 2025 Work, Energy and Power Question with Solution (24 Jan Morning shift, Q27) | JEE Arc

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JEE Arc/Physics/Work, Energy and Power

Work, Energy and Power: JEE Main 2025 Physics question

JEE Main 2025 · 24 Jan, Morning shift · Q27

JEE Main 202524 Jan, Morning shiftPhysicsEasyWork, Energy and Power70× since 2002

A force

F=\alpha+\beta x^2

acts on an object in the x-direction. The work done by the force is 5 J when the object is displaced by 1 m. If the constant

\alpha=1

N then

\beta

will be

JEE Main 2025 · 24 Jan, Morning shift · Q27

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