A circular disc has radius R₁ and thickness T₁. Another circular disc made of the same material has radius R₂ and thickness T₂. If the moment of inertia of both discs are same and R₁/R₂=2 then T₁/T₂=1/(α). The value of α is _ _ _.

Rotational Motion: JEE Main 2026 Physics question

JEE Main 2026 · 22 Jan, Morning shift · Q48

JEE Main 202622 Jan, Morning shiftPhysicsMediumRotational Motion140× since 2002

A circular disc has radius

R_1

and thickness

T_1

. Another circular disc made of the same material has radius

R_2

and thickness

T_2

. If the moment of inertia of both discs are same and

\frac{R_1}{R_2}=2

then

\frac{T_1}{T_2}=\frac{1}{\alpha}

. The value of

\alpha

is ______.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2026 Rotational Motion Question with Solution (22 Jan Morning shift, Q48) | JEE Arc

JEE Main 2026 · 22 Jan, Morning shift · Q48

JEE Main 202622 Jan, Morning shiftPhysicsMediumRotational Motion140× since 2002

A circular disc has radius

R_1

and thickness

T_1

. Another circular disc made of the same material has radius

R_2

and thickness

T_2

. If the moment of inertia of both discs are same and

\frac{R_1}{R_2}=2

then

\frac{T_1}{T_2}=\frac{1}{\alpha}

. The value of

\alpha

is ______.

Your answerType your answer. Integers and decimals are accepted.