200 mL of 0.2 M HCl is mixed with 300 mL of 0.1 M NaOH. The molar heat of neutralization of this reaction is - 57.1 kJ. The increase in temperature in° C of the system on mixing is x × 10⁻². The value of x is _ _ _ _ _ _. (Nearest integer) [Given: Specific heat of water = 4.18 J g⁻¹ K⁻¹, Density of water = 1.00 g cm⁻³] [Assume no volume change on mixing)

Chemical Thermodynamics: JEE Main 2021 Chemistry question

JEE Main 2021 · 27 Aug, Morning shift · Q21

JEE Main 202127 Aug, Morning shiftChemistryHardChemical Thermodynamics84× since 2002

200 mL of 0.2 M HCl is mixed with 300 mL of 0.1 M NaOH. The molar heat of neutralization of this reaction is

-

57.1 kJ. The increase in temperature in

^\circ

C of the system on mixing is x

\times

10^

-

2. The value of x is ___________. (Nearest integer) [Given : Specific heat of water = 4.18 J g^

-

1 K^

-

1, Density of water = 1.00 g cm^

-

3] [Assume no volume change on mixing)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Chemical Thermodynamics Question with Answer (27 Aug Morning shift, Q21) | JEE Arc