PhysicsMedium100×since 2002Q8155Y = A sin(ω\omegaωt + ϕ\phiϕ₀) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is Y=A2Y = {A \over 2}Y=2A and it is moving along negative x-direction. Then the initial phase angle ϕ\phiϕ₀ will be:A5π6{{5\pi } \over 6}65πBπ3{{\pi } \over 3}3πC2π3{{2\pi } \over 3}32πDπ6{{\pi } \over 6}6πCheck answerSkip