PhysicsMedium68×since 2002Q7539When forces F1, F2, F3{F_1},\,\,{F_2},\,\,{F_3}F1,F2,F3 are acting on a particle of mass mmm such that F2{F_2}F2 and F3{F_3}F3 are mutually perpendicular, then the particle remains stationary. If the force F1{F_1}F1 is now removed then the acceleration of the particle isAF1/m{F_1}/mF1/mBF2F3/mF1{F_2}{F_3}/m{F_1}F2F3/mF1C(F2−F3)/m\left( {F{}_2 - {F_3}} \right)/m(F2−F3)/mDF2/m{F_2}/mF2/mCheck answerSkip