PhysicsHard156×since 2002Q8285What is the dimensional formula of ab−1a b^{-1}ab−1 in the equation (P+aV2)(V−b)=RT\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}(P+V2a)(V−b)=RT, where letters have their usual meaning.A[M6 L7 T4][\mathrm{M}^6 \mathrm{~L}^7 \mathrm{~T}^4][M6 L7 T4]B[M−1 L5 T3][\mathrm{M}^{-1} \mathrm{~L}^5 \mathrm{~T}^3][M−1 L5 T3]C[M0 L3 T−2][\mathrm{M}^0 \mathrm{~L}^3 \mathrm{~T}^{-2}][M0 L3 T−2]D[ML2 T−2][\mathrm{ML}^2 \mathrm{~T}^{-2}][ML2 T−2]Check answerSkip