Wavelength of light used in an optical instrument are … and … then ratio of their respective resolving powers (corresponding to … and … ) is :

Option D. The resolving power (RP) of an optical instrument is inversely proportional to the wavelength (λ) of light used. So, if we denote the resolving powers corresponding to λ₁ and λ₂ as RP₁ and RP₂ respectively, we can express this relationship as :

Geometrical Optics

JEE Main 2002 · Annual, Paper 1 · Q7059

PhysicsMedium105×since 2002Q7059

Wavelength of light used in an optical instrument are

{\lambda _1} = 4000\mathop A\limits^ \circ

and

{\lambda _2} = 5000\mathop A\limits^ \circ ,

then ratio of their respective resolving powers (corresponding to

{\lambda _1}

and

{\lambda _2}

) is :

Geometrical Optics

JEE Main 2002 · Annual, Paper 1 · Q7059

PhysicsMedium105×since 2002Q7059

Wavelength of light used in an optical instrument are

{\lambda _1} = 4000\mathop A\limits^ \circ

and

{\lambda _2} = 5000\mathop A\limits^ \circ ,

then ratio of their respective resolving powers (corresponding to

{\lambda _1}

and

{\lambda _2}

) is :

Geometrical Optics

More on Geometrical Optics

Geometrical Optics

More on Geometrical Optics