PhysicsMedium226×since 2002Q6487Two sources of equal emfemfemf are connected to an external resistance R.R.R. The internal resistance of the two sources are R1{R_1}R1 and R2(R1>R1).{R_2}\left( {{R_1} > {R_1}} \right).R2(R1>R1). If the potential difference across the source having internal resistance R2{R_2}R2 is zero, thenAR=R2−R1R = {R_2} - {R_1}R=R2−R1BR=R2×(R1+R2)/(R2−R1)R = {R_2} \times \left( {{R_1} + {R_2}} \right)/\left( {{R_2} - {R_1}} \right)R=R2×(R1+R2)/(R2−R1)CR=R1R2/(R2−R1)R = {R_1}{R_2}/\left( {{R_2} - {R_1}} \right)R=R1R2/(R2−R1)DR=R1R2/(R1−R2)R = {R_1}{R_2}/\left( {{R_1} - {R_2}} \right)R=R1R2/(R1−R2)Check answerSkip