PhysicsMedium159×since 2002Q7277Two particles of equal mass 'mmm' move in a circle of radius 'rrr' under the action of their mutual gravitational attraction. The speed of each particle will be :AGm4r\sqrt{\frac{G m}{4 r}}4rGmBGm2r\sqrt{\frac{G m}{2 r}}2rGmCGmr\sqrt{\frac{G m}{r}}rGmD4Gmr\sqrt{\frac{4 G m}{r}}r4GmCheck answerSkip