PhysicsMedium145×since 2002Q6613Two identical photo-cathodes receive light of frequencies f1{f_1}f1 and f2{f_2}f2. If the velocities of the photo electrons (of mass mmm ) coming out are respectively v1{v_1}v1 and v2,{v_2},v2, thenAv12−v22=2hm(f1−f2)v_1^2 - v_2^2 = {{2h} \over m}\left( {{f_1} - {f_2}} \right)v12−v22=m2h(f1−f2)Bv1+v2=[2hm(f1+f2)]1/2{v_1} + {v_2} = {\left[ {{{2h} \over m}\left( {{f_1} + {f_2}} \right)} \right]^{1/2}}v1+v2=[m2h(f1+f2)]1/2Cv12+v22=2hm(f1+f2)v_1^2 + v_2^2 = {{2h} \over m}\left( {{f_1} + {f_2}} \right)v12+v22=m2h(f1+f2)Dv1−v2=[2hm(f1−f2)]1/2{v_1} - {v_2} = {\left[ {{{2h} \over m}\left( {{f_1} - {f_2}} \right)} \right]^{1/2}}v1−v2=[m2h(f1−f2)]1/2Check answerSkip