PhysicsHard159×since 2002Q7269Two identical particles of mass 1 kg each go round a circle of radius R, under the action of their mutual gravitational attraction. The angular speed of each particle is :AG2R3\sqrt {{G \over {2{R^3}}}}2R3GB12GR3{1 \over 2}\sqrt {{G \over {{R^3}}}}21R3GC12R1G{1 \over {2R}}\sqrt {{1 \over G}}2R1G1D2GR3{{2G} \over {{R^3}}}R32GCheck answerSkip