PhysicsMedium251×since 2002Q7518Two different wires having lengths L₁ and L₂, and respective temperature coefficient of linear expansion α\alphaα₁ and α\alphaα₂, are joined end-to-end. Then the effective temperature coefficient of linear expansion is :A2α1α22\sqrt {{\alpha _1}{\alpha _2}}2α1α2B4α1α2α1+α2L2L1(L2+L1)24{{{\alpha _1}{\alpha _2}} \over {{\alpha _1} + {\alpha _2}}}{{{L_2}{L_1}} \over {{{\left( {{L_2} + {L_1}} \right)}^2}}}4α1+α2α1α2(L2+L1)2L2L1Cα1+α22{{{\alpha _1} + {\alpha _2}} \over 2}2α1+α2Dα1L1+α2L2L1+L2{{{\alpha _1}{L_1} + {\alpha _2}{L_2}} \over {{L_1} + {L_2}}}L1+L2α1L1+α2L2Check answerSkip