MathematicsEasy92×since 2002Q4677Two common tangents to the circle x2+y2=2a2{x^2} + {y^2} = 2{a^2}x2+y2=2a2 and parabola y2=8ax{y^2} = 8axy2=8ax are :Ax=±(y+2a)x = \pm \left( {y + 2a} \right)x=±(y+2a)By=±(x+2a)y = \pm \left( {x + 2a} \right)y=±(x+2a)Cx=±(y+a)x = \pm \left( {y + a} \right)x=±(y+a)Dy=±(x+a)y = \pm \left( {x + a} \right)y=±(x+a)Check answerSkip