PhysicsEasy65×since 2002Q7876Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by XP(t)=αt+βt2{X_P}(t) = \alpha t + \beta {t^2}XP(t)=αt+βt2 and XQ(t)=ft−t2{X_Q}(t) = ft - {t^2}XQ(t)=ft−t2. At what time, both the buses have same velocity?Aα−f1+β{{\alpha - f} \over {1 + \beta }}1+βα−fBα+f2(β−1){{\alpha + f} \over {2(\beta - 1)}}2(β−1)α+fCα+f2(1+β){{\alpha + f} \over {2(1 + \beta )}}2(1+β)α+fDf−α2(1+β){{f - \alpha } \over {2(1 + \beta )}}2(1+β)f−αCheck answerSkip