MathematicsHard249×since 2002Q2489The vertices B and C of a Δ\DeltaΔABC lie on the line, x+23=y−10=z4{{x + 2} \over 3} = {{y - 1} \over 0} = {z \over 4}3x+2=0y−1=4z such that BC = 5 units. Then the area (in sq. units) of this triangle, given that the point A(1, –1, 2), is :A6B5175\sqrt {17}517C34\sqrt {34}34D2342\sqrt {34}234Check answerSkip