PhysicsMedium49×since 2003Q7630The vertical component of the earth's magnetic field is 6×10−5 T6 \times 10^{-5} \mathrm{~T}6×10−5 T at any place where the angle of dip is 37∘37^{\circ}37∘. The earth's resultant magnetic field at that place will be (\left(\right.(Given tan37∘=34)\left.\tan 37^{\circ}=\frac{3}{4}\right)tan37∘=43)A8×10−5 T8 \times 10^{-5} \mathrm{~T}8×10−5 TB6×10−5 T6 \times 10^{-5} \mathrm{~T}6×10−5 TC5×10−4 T5 \times 10^{-4} \mathrm{~T}5×10−4 TD1×10−4 T1 \times 10^{-4} \mathrm{~T}1×10−4 TCheck answerSkip