MathematicsMedium244×since 2002Q4471The values of α\alphaα, for which ∣132α+32113α+132α+33α+10∣=0\left|\begin{array}{ccc}1 & \frac{3}{2} & \alpha+\frac{3}{2} \\ 1 & \frac{1}{3} & \alpha+\frac{1}{3} \\ 2 \alpha+3 & 3 \alpha+1 & 0\end{array}\right|=0112α+323313α+1α+23α+310=0, lie in the intervalA(−2,1)(-2,1)(−2,1)B(−32,32)\left(-\frac{3}{2}, \frac{3}{2}\right)(−23,23)C(−3,0)(-3,0)(−3,0)D(0,3)(0,3)(0,3)Check answerSkip