MathematicsEasy210×since 2002Q3454The value of the integral ∫1/22tan−1xxdx\int\limits_{1/2}^2 {{{{{\tan }^{ - 1}}x} \over x}dx}1/2∫2xtan−1xdx is equal to :Aπ2loge2{\pi \over 2}{\log _e}22πloge2Bπ4loge2{\pi \over 4}{\log _e}24πloge2C12loge2{1 \over 2}{\log _e}221loge2Dπloge2\pi {\log _e}2πloge2Check answerSkip