MathematicsEasy210×since 2002Q3414The value of the integral ∫−11log(x+x2+1)dx\int\limits_{ - 1}^1 {\log \left( {x + \sqrt {{x^2} + 1} } \right)dx}−1∫1log(x+x2+1)dx is :A2B0C−-−1D1Check answerSkip