MathematicsHard210×since 2002Q3416The value of ∫−1212((x+1x−1)2+(x−1x+1)2−2)12dx\int\limits_{{{ - 1} \over {\sqrt 2 }}}^{{1 \over {\sqrt 2 }}} {{{\left( {{{\left( {{{x + 1} \over {x - 1}}} \right)}^2} + {{\left( {{{x - 1} \over {x + 1}}} \right)}^2} - 2} \right)}^{{1 \over 2}}}dx}2−1∫21((x−1x+1)2+(x+1x−1)2−2)21dx is :Alog_e 4Blog_e 16C2log_e 16D4log_e (3 + 22{\sqrt 2 }2)Check answerSkip