MathematicsMedium210×since 2002Q3391The value of ∫02πxsin8xsin8x+cos8xdx\int\limits_0^{2\pi } {{{x{{\sin }^8}x} \over {{{\sin }^8}x + {{\cos }^8}x}}} dx0∫2πsin8x+cos8xxsin8xdx is equal to :A4π\piπB2π\piπCπ\piπ²D2π\piπ²Check answerSkip