PhysicsMedium53×since 2003Q7804The trajectory of projectile, projected from the ground is given by y=x−x220y=x-\frac{x^{2}}{20}y=x−20x2. Where xxx and yyy are measured in meter. The maximum height attained by the projectile will be.A10 mB5 mC200 mD102\sqrt22 mCheck answerSkip