PhysicsEasy100×since 2002Q8211The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination α\alphaα, is given by :A2πL/(gcosα)2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \cos \alpha)}2πL/(gcosα)B2πL/(gsinα)2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \sin \alpha)}2πL/(gsinα)C2πL/g2 \pi \sqrt{\mathrm{L} / \mathrm{g}}2πL/gD2πL/(gtanα)2 \pi \sqrt{\mathrm{L} /(\mathrm{g} \tan \alpha)}2πL/(gtanα)Check answerSkip