PhysicsHard159×since 2002Q7212The time period of a satellite, revolving above earth's surface at a height equal to R\mathrm{R}R will be (Given g=π2 m/s2,R=g=\pi^{2} \mathrm{~m} / \mathrm{s}^{2}, \mathrm{R}=g=π2 m/s2,R= radius of earth)A32R\sqrt{32 R}32RB4R\sqrt{4 \mathrm{R}}4RC8R\sqrt{8 R}8RD2R\sqrt{2 R}2RCheck answerSkip