MathematicsMedium64×since 2002Q2909The term independent of xxx in expansion of (x+1x2/3−x1/3+1−x−1x−x1/2)10{\left( {{{x + 1} \over {{x^{2/3}} - {x^{1/3}} + 1}} - {{x - 1} \over {x - {x^{1/2}}}}} \right)^{10}}(x2/3−x1/3+1x+1−x−x1/2x−1)10 isA4B120C210D310Check answerSkip