MathematicsMedium178×since 2002Q5339The sum ∑n=1∞2n2+3n+4(2n)!\sum\limits_{n = 1}^\infty {{{2{n^2} + 3n + 4} \over {(2n)!}}}n=1∑∞(2n)!2n2+3n+4 is equal to :A11e2+72e{{11e} \over 2} + {7 \over {2e}}211e+2e7B13e4+54e−4{{13e} \over 4} + {5 \over {4e}} - 4413e+4e5−4C11e2+72e−4{{11e} \over 2} + {7 \over {2e}} - 4211e+2e7−4D13e4+54e{{13e} \over 4} + {5 \over {4e}}413e+4e5Check answerSkip