The sum of the real roots of the equation …, is equal to :

Option B. x(-3x … (x + 2) - 2x(x - 3)) + (– 6) (2(x + 2) + 3 (x – 3)) + (–1) (4x + 3 (–3x))

Matrices and Determinants

JEE Main 2019 · 10 Apr, Evening shift · Q4449

MathematicsEasy244×since 2002Q4449

The sum of the real roots of the equation

\left| {\matrix{ x & { - 6} & { - 1} \cr 2 & { - 3x} & {x - 3} \cr { - 3} & {2x} & {x + 2} \cr } } \right| = 0

, is equal to :