MathematicsMedium178×since 2002Q5308The sum of the following series 1+6+9(12+22+32)7+12(12+22+32+42)91 + 6 + {{9\left( {{1^2} + {2^2} + {3^2}} \right)} \over 7} + {{12\left( {{1^2} + {2^2} + {3^2} + {4^2}} \right)} \over 9}1+6+79(12+22+32)+912(12+22+32+42) +15(12+22+...+52)11+.....+ {{15\left( {{1^2} + {2^2} + ... + {5^2}} \right)} \over {11}} + .....+1115(12+22+...+52)+..... up to 15 terms, is :A7520B7510C7830D7820Check answerSkip