MathematicsHard115×since 2008Q4376The statement (p∧q)⇒(p∧r)(p \wedge q) \Rightarrow(p \wedge r)(p∧q)⇒(p∧r) is equivalent to :Aq⇒(p∧r)q \Rightarrow(p \wedge r)q⇒(p∧r)Bp⇒(p∧r)p\Rightarrow(\mathrm{p} \wedge \mathrm{r})p⇒(p∧r)C(p∧r)⇒(p∧q)(\mathrm{p} \wedge \mathrm{r}) \Rightarrow(\mathrm{p} \wedge \mathrm{q})(p∧r)⇒(p∧q)D(p∧q)⇒r(p \wedge q) \Rightarrow r(p∧q)⇒rCheck answerSkip