MathematicsEasy38×since 2002Q3634The solution of the differential equation dydx=−(x2+3y23x2+y2),y(1)=0\frac{d y}{d x}=-\left(\frac{x^2+3 y^2}{3 x^2+y^2}\right), y(1)=0dxdy=−(3x2+y2x2+3y2),y(1)=0 is :Aloge∣x+y∣+xy(x+y)2=0\log _e|x+y|+\frac{x y}{(x+y)^2}=0loge∣x+y∣+(x+y)2xy=0Bloge∣x+y∣−xy(x+y)2=0\log _e|x+y|-\frac{x y}{(x+y)^2}=0loge∣x+y∣−(x+y)2xy=0Cloge∣x+y∣+2xy(x+y)2=0\log _e|x+y|+\frac{2 x y}{(x+y)^2}=0loge∣x+y∣+(x+y)22xy=0Dloge∣x+y∣−2xy(x+y)2=0\log _e|x+y|-\frac{2 x y}{(x+y)^2}=0loge∣x+y∣−(x+y)22xy=0Check answerSkip