MathematicsMedium38×since 2002Q3516The solution of the differential equation, dydx{{dy} \over {dx}}dxdy = (x – y)², when y(1) = 1, is :A−-− log_e ∣1+x−y1−x+y∣\left| {{{1 + x - y} \over {1 - x + y}}} \right|1−x+y1+x−y = x + y −-− 2Blog_e ∣2−x2−y∣\left| {{{2 - x} \over {2 - y}}} \right|2−y2−x = x −-− yClog_e ∣2−y2−x∣\left| {{{2 - y} \over {2 - x}}} \right|2−x2−y = 2(y −-− 1)D−-− log_e ∣1−x+y1+x−y∣\left| {{{1 - x + y} \over {1 + x - y}}} \right|1+x−y1−x+y = 2(x −-− 1)Check answerSkip