MathematicsMedium249×since 2002Q2486The shortest distance between the lines x2=y2=z1{x \over 2} = {y \over 2} = {z \over 1}2x=2y=1z and x+2−1=y−48=z−54{{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}−1x+2=8y−4=4z−5 lies in the interval :A[0, 1)B[1, 2)C(2, 3]D(3, 4]Check answerSkip